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Problem
Problem
If
log
P
A
x
=
2
\log_{PA} x = 2
lo
g
P
A
x
=
2
,
log
P
B
x
=
3
\log_{PB} x = 3
lo
g
P
B
x
=
3
,
log
x
P
C
=
4
\log_x PC = 4
lo
g
x
P
C
=
4
, then
log
P
D
x
\log_{PD} x
lo
g
P
D
x
is equal to a.
7
12
\frac{7}{12}
12
7
b.
12
7
\frac{12}{7}
7
12
c.
−
7
12
-\frac{7}{12}
−
12
7
d.
−
6
19
-\frac{6}{19}
−
19
6
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