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Mathematics
Mathematics
Problem
If
y
=
sec
x
−
tan
x
sec
x
+
tan
x
y = \frac{\sec x - \tan x}{\sec x + \tan x}
y
=
s
e
c
x
+
t
a
n
x
s
e
c
x
−
t
a
n
x
, then
d
y
d
x
\frac{dy}{dx}
d
x
d
y
equals a.
2
sec
x
(
sec
x
−
tan
x
)
2 \sec x (\sec x - \tan x)
2
sec
x
(
sec
x
−
tan
x
)
b.
−
2
sec
x
(
sec
x
−
tan
x
)
2
-2 \sec x (\sec x - \tan x)^2
−
2
sec
x
(
sec
x
−
tan
x
)
2
c.
2
sec
x
(
sec
x
+
tan
x
)
2
2 \sec x (\sec x + \tan x)^2
2
sec
x
(
sec
x
+
tan
x
)
2
d.
−
2
sec
x
(
sec
x
+
tan
x
)
2
-2 \sec x (\sec x + \tan x)^2
−
2
sec
x
(
sec
x
+
tan
x
)
2
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