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Chemistry
Chemistry
Problem
50 mL of 0.1 M NaOH is added to 60 mL of 0.15 M
H
3
P
O
4
H_3PO_4
H
3
P
O
4
solution (
K
1
K_1
K
1
,
K
2
K_2
K
2
and
K
3
K_3
K
3
for
H
3
P
O
4
H_3PO_4
H
3
P
O
4
are
10
−
3
10^{-3}
1
0
−
3
,
10
−
8
10^{-8}
1
0
−
8
and
10
−
13
10^{-13}
1
0
−
13
respectively). The pH of the mixture would be about (
log
2
=
0.3
\log 2 = 0.3
lo
g
2
=
0.3
)
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