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Problem
Problem
Number of ordered pairs
(
x
,
y
)
(x, y)
(
x
,
y
)
which satisfies the
relation
x
4
+
1
8
x
2
=
sin
2
y
⋅
cos
2
y
,
where
y
∈
[
0
,
2
π
]
.
\text{relation } \frac{x^4 + 1}{8x^2} = \sin^2 y \cdot \cos^2 y, \text{ where } y \in [0, 2\pi].
relation
8
x
2
x
4
+
1
=
sin
2
y
⋅
cos
2
y
,
where
y
∈
[
0
,
2
π
]
.
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