Introduction to Quantum Mechanics · Problem 5.11

Identical Particles — David J. Griffiths

Physics — Quantum Mechanics · laughlin_wave_function

Problem

In Section 5.1 we found that for noninteracting particles the wave function can be expressed as a product of single-particle states (Equation 5.9)—or, for identical particles, as a symmetrized/antisymmetrized linear combination of such states (Equations 5.20 and 5.21). For interacting particles this is no longer the case. A famous example is the Laughlin wave function, which is an approximation to the ground state of NN electrons confined to two dimensions in a perpendicular magnetic field of strength BB (the setting for the fractional quantum Hall effect). The Laughlin wave function is ψ(z1,z2,…,zN)=A[∏j<kN(zj−zk)q]exp⁡[−12∑kN∣zk∣2]\psi(z_1, z_2, \ldots, z_N) = A \left[\prod_{j<k}^{N} (z_j - z_k)^q\right] \exp\left[-\frac{1}{2}\sum_k^N |z_k|^2\right] where qq is a positive odd integer and zj≡eB2ℏc(xj+iyj).z_j \equiv \sqrt{\frac{eB}{2\hbar c}}(x_j + i y_j). (Spin is not at issue here; in the ground state all the electrons have spin down with respect to the direction of B\mathbf{B}, and that is a trivially symmetric configuration.) (a) Show that ψ\psi has the proper antisymmetry for fermions. (b) For q=1q = 1, ψ\psi describes noninteracting particles (by which I mean that it can be written as a single Slater determinant—see Problem 5.8). This is true for any NN, but check it explicitly for N=3N = 3. What single particle states are occupied in this case? (c) For values of qq greater than 1, ψ\psi cannot be written as a single Slater determinant, and describes interacting particles (in practice, Coulomb repulsion of the electrons). It can, however, be written as a sum of Slater determinants. Show that, for q=3q = 3 and N=2N = 2, ψ\psi can be written as a sum of two Slater determinants. Comment: In the noninteracting case (b) we can describe the wave function as "three particles occupying the three single-particle states ψa\psi_a, ψb\psi_b and ψc\psi_c," but in the interacting case (c), no corresponding statement can be made; in that case, the different Slater determinants that make up ψ\psi correspond to occupation of different sets of single-particle states.

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