A student sketches the following velocity–time graph for a scooter:
• From t=0s to t=4s: a horizontal line at 5m/s.
• At t=4s: an abrupt vertical jump to 15m/s.
• From t=4s to t=8s: a horizontal line at 15m/s.
The student claims that this represents “uniform acceleration for 4 s followed by uniform motion.”
a. (a) Identify the error in the graph with respect to uniform acceleration.
b. (b) Describe how the correct velocity–time graph should be drawn for this motion.