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Physics
Physics
Problem
A
0.50
kg
0.50\,\text{kg}
0.50
kg
quantity of water (specific heat
4186
J
kg
−
1
°C
−
1
4186\,\text{J}\,\text{kg}^{-1}\,\text{°C}^{-1}
4186
J
kg
−
1
°C
−
1
) absorbs
6.3
kJ
6.3\,\text{kJ}
6.3
kJ
of energy. Calculate the temperature change of the water. Give your answer to the nearest
0.1
∘
C
0.1\,^{\circ}\text{C}
0.1
∘
C
.
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