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Mathematics
Problem
The integral
∫
1
2
e
x
⋅
x
x
(
2
+
log
e
x
)
d
x
\int_{1}^{2} e^x \cdot x^x (2 + \log_e x) dx
∫
1
2
e
x
⋅
x
x
(
2
+
lo
g
e
x
)
d
x
equals (a)
e
(
4
e
+
1
)
e(4e + 1)
e
(
4
e
+
1
)
(b)
4
e
2
−
1
4e^2 - 1
4
e
2
−
1
(c)
e
(
4
e
−
1
)
e(4e - 1)
e
(
4
e
−
1
)
(d)
e
(
2
e
−
1
)
e(2e - 1)
e
(
2
e
−
1
)
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