Let us try to deduce the restriction on lz from another angle. Consider a superposition of two allowed lz eigenstates:
ψ(ρ,ϕ)=A(ρ)eiϕlz/ℏ+B(ρ)eiϕlz′/ℏ
By demanding that upon a 2π rotation we get the same physical state (not necessarily the same state vector), show that lz−lz′=mℏ, where m is an integer. By arguing on the grounds of symmetry that the allowed values of lz must be symmetric about zero, show that these values are either …,3ℏ/2,ℏ/2,−ℏ/2,−3ℏ/2,… or …,2ℏ,ℏ,0,−ℏ,−2ℏ,…. It is not possible to restrict lz any further this way.