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Physics
Physics
Problem
For a
0.5
kg
0.5\,\text{kg}
0.5
kg
particle the potential energy varies with position as
V
(
x
)
=
4
x
2
J
V(x)=4x^{2}\,\text{J}
V
(
x
)
=
4
x
2
J
(with
x
x
x
in metres). If the particle is released from rest at
x
=
0.25
m
x=0.25\,\text{m}
x
=
0.25
m
, what is the magnitude of its initial acceleration? a)
8
m
s
−
2
8\,\text{m\,s}^{-2}
8
m
s
−
2
b)
4
m
s
−
2
4\,\text{m\,s}^{-2}
4
m
s
−
2
c)
2
m
s
−
2
2\,\text{m\,s}^{-2}
2
m
s
−
2
d)
16
m
s
−
2
16\,\text{m\,s}^{-2}
16
m
s
−
2
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