Classical Electrodynamics · Problem 6.4

Plane Electromagnetic Waves and Wave Propagation — John David Jackson

Physics — E&M · rotating-magnetized-conducting-sphere

Problem

A uniformly magnetized and conducting sphere of radius RR and total magnetic moment m=4πMR3/3m = 4\pi MR^3/3 rotates about its magnetization axis with angular speed ω\omega. In the steady state no current flows in the conductor. The motion is nonrelativistic; the sphere has no excess charge on it. (a) By considering Ohm's law in the moving conductor, show that the motion induces an electric field and a uniform volume charge density in the conductor, ρ=−mω/πc2R3.\rho = -m\omega/\pi c^2 R^3. (b) Because the sphere is electrically neutral, there is no monopole electric field outside. Use symmetry arguments to show that the lowest possible electric multipolarity is quadrupole. Show that only a quadrupole field exists outside and that the quadrupole moment tensor has nonvanishing components, Q33=−4mωR2/3c2,Q11=Q22=−Q33/2.Q_{33} = -4m\omega R^2/3c^2, \quad Q_{11} = Q_{22} = -Q_{33}/2. (c) By considering the radial electric fields inside and outside the sphere, show that the necessary surface-charge density σ(θ)\sigma(\theta) is σ(θ)=14πR2⋅4mω3c2⋅[1−52 P2(cos⁡θ)]\sigma(\theta) = \frac{1}{4\pi R^2} \cdot \frac{4m\omega}{3c^2} \cdot \left[1 - \frac{5}{2}\, P_2(\cos\theta)\right] (d) The rotating sphere serves as a unipolar induction device if a stationary circuit is attached by a slip ring to the pole and a sliding contact to the equator. Show that the line integral of the electric field from the equator contact to the pole contact (by any path) is E=μ0mω/4πR\mathcal{E} = \mu_0 m\omega/4\pi R. [See Landau and Lifshitz, Electrodynamics of Continuous Media, p. 221, for an alternative discussion of this electromotive force.]

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