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Mathematics
Mathematics
Problem
The area (in sq. units) of the smaller of the two circles that touch the parabola,
y
2
=
4
x
y^2 = 4x
y
2
=
4
x
at the point
(
1
,
2
)
(1, 2)
(
1
,
2
)
and the x-axis is : [JEE-MAIN ONLINE-2019] (1)
4
π
(
2
−
2
)
4\pi(2 - \sqrt{2})
4
π
(
2
−
2
)
(2)
8
π
(
3
−
2
2
)
8\pi(3 - 2\sqrt{2})
8
π
(
3
−
2
2
)
(3)
4
π
(
3
+
2
)
4\pi(3 + \sqrt{2})
4
π
(
3
+
2
)
(4)
8
π
(
2
−
2
)
8\pi(2 - \sqrt{2})
8
π
(
2
−
2
)
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