Physics

Physics

Problem

A proton is fired from very far away towards a nucleus with charge Q=120eQ = 120 e, where ee is the electronic charge. It makes a closest approach of 10 fm to the nucleus. The de Broglie wavelength (in units of fm) of the proton at its start is: (take the proton mass, mp=(5/3)×10−27 kgm_p = (5/3) \times 10^{-27} \text{ kg}; h/e=4.2×10−15 Js/Ch/e = 4.2 \times 10^{-15} \text{ Js/C}; 14πε0=9×109 m/F\frac{1}{4\pi\varepsilon_0} = 9 \times 10^9 \text{ m/F}; 1 fm=10−15 m1 \text{ fm} = 10^{-15} \text{ m} [2012-1])

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