Mathematics

Mathematics

Problem

15. Prove that (a⃗+b⃗)⋅(a⃗+b⃗)=∣a⃗∣2+∣b⃗∣2(\vec{a}+\vec{b}) \cdot(\vec{a}+\vec{b})=|\vec{a}|^{2}+|\vec{b}|^{2}, if and only if a⃗,b⃗\vec{a}, \vec{b} are perpendicular, given a⃗≠0→,b⃗≠0→\vec{a} \neq \overrightarrow{0}, \vec{b} \neq \overrightarrow{0}.

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