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Mathematics
Problem
15. Prove that
(
a
⃗
+
b
⃗
)
⋅
(
a
⃗
+
b
⃗
)
=
∣
a
⃗
∣
2
+
∣
b
⃗
∣
2
(\vec{a}+\vec{b}) \cdot(\vec{a}+\vec{b})=|\vec{a}|^{2}+|\vec{b}|^{2}
(
a
+
b
)
⋅
(
a
+
b
)
=
∣
a
∣
2
+
∣
b
∣
2
, if and only if
a
⃗
,
b
⃗
\vec{a}, \vec{b}
a
,
b
are perpendicular, given
a
⃗
≠
0
→
,
b
⃗
≠
0
→
\vec{a} \neq \overrightarrow{0}, \vec{b} \neq \overrightarrow{0}
a
=
0
,
b
=
0
.
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