Mathematics

Problem

For the relation

x\tan y+y=0

, find

\dfrac{dy}{dx}

in terms of

x

and

y

. a)

\displaystyle\frac{\tan y}{x\sec^{2}y+1}

\displaystyle\frac{-\tan y}{x\sec^{2}y-1}

\displaystyle\frac{-\tan y}{x\sec^{2}y+1}

\displaystyle\frac{-\tan y}{x+1}