Mathematics — Real Analysis · improper-integrals-cauchy-principal-value
Problem
a) Compute p.v.∫−111/xdx.
b) Compute limϵ→0+(∫−1−ϵ1/xdx+∫2ϵ11/xdx) and show it is not equal to the principal value.
c) Show that if f is integrable on [a,b], then p.v.∫abf=∫abf (for an arbitrary c∈(a,b)).
d) Suppose f:[−1,1]→R is an odd function (f(−x)=−f(x)) that is integrable on [−1,−ϵ] and [ϵ,1] for all ϵ>0. Prove that p.v.∫−11f=0.
e) Suppose f:[−1,1]→R is continuous and differentiable at 0. Show that p.v.∫−11xf(x)dx exists.
(Recall: It is sometimes desirable to assign a value to integrals that normally cannot be interpreted even as improper integrals, e.g. ∫−111/xdx. Suppose f:[a,b]→R is a function and a<c<b, where f is Riemann integrable on the intervals [a,c−ϵ] and [c+ϵ,b] for all ϵ>0. Define the Cauchy principal value of ∫abf as
p.v.∫abf:=ϵ→0+lim(∫ac−ϵf+∫c+ϵbf),
if the limit exists.)