Mathematics

Mathematics

Problem

For a body moving along a straight line, the position at time tt seconds is s(t)=t3−6t2+9t+4s(t)=t^{3}-6t^{2}+9t+4 metres. Calculate its acceleration at t=2t=2 seconds. a) −12 m/s2-12\text{ m/s}^{2} b) 12 m/s212\text{ m/s}^{2} c) 0 m/s20\text{ m/s}^{2} d) 6 m/s26\text{ m/s}^{2}

Browse the problem library