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Mathematics
Problem
If
d
y
d
x
+
3
cos
2
x
y
=
1
cos
2
x
\frac{dy}{dx} + \frac{3}{\cos^2 x} y = \frac{1}{\cos^2 x}
d
x
d
y
+
c
o
s
2
x
3
y
=
c
o
s
2
x
1
,
x
∈
(
−
π
3
,
π
3
)
x \in \left(-\frac{\pi}{3}, \frac{\pi}{3}\right)
x
∈
(
−
3
π
,
3
π
)
, and
y
(
π
4
)
=
4
3
y\left(\frac{\pi}{4}\right) = \frac{4}{3}
y
(
4
π
)
=
3
4
, then
y
(
−
π
4
)
y\left(-\frac{\pi}{4}\right)
y
(
−
4
π
)
equals : [JEE-MAIN ONLINE-20] (1)
1
3
+
e
6
\frac{1}{3} + e^6
3
1
+
e
6
(2)
1
3
\frac{1}{3}
3
1
(3)
−
4
3
-\frac{4}{3}
−
3
4
(4)
1
3
+
e
3
\frac{1}{3} + e^3
3
1
+
e
3
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