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Mathematics
Mathematics
Problem
Which of the following equals
sin
2
θ
\sin 2\theta
sin
2
θ
? a)
cos
2
θ
−
sin
2
θ
\cos^{2}\theta-\sin^{2}\theta
cos
2
θ
−
sin
2
θ
b)
sin
θ
cos
θ
\sin\theta\cos\theta
sin
θ
cos
θ
c)
2
sin
θ
cos
θ
2\sin\theta\cos\theta
2
sin
θ
cos
θ
d)
2
tan
θ
1
−
tan
2
θ
\dfrac{2\tan\theta}{1-\tan^{2}\theta}
1
−
tan
2
θ
2
tan
θ
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