Chemistry

Chemistry

Problem

A chemical plant produces sulfur trioxide in two consecutive reactions at constant pressure, as shown below. Step 1 S(s) + O₂(g) → SO₂(g)  ΔH1=−297 kJ\Delta H_1 = -297\,\text{kJ} Step 2 2 SO₂(g) + O₂(g) → 2 SO₃(g) ΔH2=−198 kJ\Delta H_2 = -198\,\text{kJ} Which of the following best explains why the total enthalpy change for converting S(s) to SO₃(g) equals the sum of ΔH1\Delta H_1 and ΔH2\Delta H_2? a) Energy is conserved, so the heat released in each step adds to give the overall heat released. b) Because both steps are exothermic, their negative ΔH\Delta H values reinforce each other and therefore must be added. c) Enthalpy is a state function, so the overall ΔH\Delta H depends only on the initial and final states and is independent of the pathway taken. d) The intermediate SO2\mathrm{SO_2} is formed and consumed, causing its enthalpy to cancel, leaving only the second step to contribute to the overall ΔH\Delta H.

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