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Mathematics
Mathematics
Problem
If
α
\alpha
α
and
β
\beta
β
(
α
>
β
\alpha > \beta
α
>
β
) are roots of the equation
x
2
−
2
x
+
3
−
2
2
=
0
,
then the value of
x^2 - \sqrt{2}x + \sqrt{3 - 2\sqrt{2}} = 0, \text{ then the value of}
x
2
−
2
x
+
3
−
2
2
=
0
,
then the value of
(
cos
−
1
α
+
tan
−
1
α
+
tan
−
1
β
)
(\cos^{-1} \alpha + \tan^{-1} \alpha + \tan^{-1} \beta)
(
cos
−
1
α
+
tan
−
1
α
+
tan
−
1
β
)
is equal to a.
3
π
8
\frac{3\pi}{8}
8
3
π
b.
5
π
8
\frac{5\pi}{8}
8
5
π
c.
7
π
8
\frac{7\pi}{8}
8
7
π
d.
π
3
\frac{\pi}{3}
3
π
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