Chemistry

Problem

Given:

\text{Hg}_2^{2+} + 2\text{e}^- \longrightarrow 2\text{Hg}

E^0 = 0.789\text{ V}

and

\text{Hg}^{2+} + 2\text{e}^- \longrightarrow \text{Hg}

E^0 = 0.854\text{ V}

, calculate the equilibrium constant for

\text{Hg}_2^{2+} \rightleftharpoons \text{Hg} + \text{Hg}^{2+}

. (a)

3.13 \times 10^{-3}

(b)

3.13 \times 10^{-4}

(c)

6.26 \times 10^{-3}

(d)

6.26 \times 10^{-4}