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Mathematics
Mathematics
Problem
If
∫
0
π
/
2
sin
x
⋅
log
(
sin
x
)
d
x
=
log
(
K
e
)
\int_0^{\pi/2} \sin x \cdot \log(\sin x) dx = \log\left(\frac{K}{e}\right)
∫
0
π
/2
sin
x
⋅
lo
g
(
sin
x
)
d
x
=
lo
g
(
e
K
)
. Then, the value of
K
K
K
is ...
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