JEE Advanced 2012 Paper 1 Mathematics Q17

Mathematics

Problem

The value of 6+log⁡3/2(1324−1324−1324−⋯)\displaystyle 6+\log_{3/2}\left(\frac1{3\sqrt2}\sqrt{4-\frac1{3\sqrt2}\sqrt{4-\frac1{3\sqrt2}\sqrt{4-\cdots}}}\right) is

Browse the problem library