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Mathematics
Mathematics
Problem
Show that
(
sin
α
cos
β
+
cos
α
sin
β
)
2
+
(
cos
α
cos
β
−
sin
α
sin
β
)
2
=
1
(\sin\alpha\cos\beta + \cos\alpha\sin\beta)^2 + (\cos\alpha\cos\beta - \sin\alpha\sin\beta)^2 = 1
(
sin
α
cos
β
+
cos
α
sin
β
)
2
+
(
cos
α
cos
β
−
sin
α
sin
β
)
2
=
1
for all real values of
α
\alpha
α
and
β
\beta
β
.
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