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Mathematics
Mathematics
Problem
For
g
(
x
)
=
cot
(
2
x
+
π
3
)
g(x)=\cot\!\left(2x+\dfrac{\pi}{3}\right)
g
(
x
)
=
cot
(
2
x
+
3
π
)
, what is
g
′
(
π
6
)
g'\!\left(\dfrac{\pi}{6}\right)
g
′
(
6
π
)
? a)
−
4
3
-\dfrac{4}{3}
−
3
4
b)
−
16
3
-\dfrac{16}{3}
−
3
16
c)
−
8
3
-\dfrac{8}{3}
−
3
8
d)
8
3
\dfrac{8}{3}
3
8
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