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JEE Advanced 2013 Paper 1 Mathematics Q9
Mathematics
Problem
Perpendiculars are drawn from points on the line
x
+
2
2
=
y
+
1
−
1
=
z
3
\dfrac{x+2}{2}=\dfrac{y+1}{-1}=\dfrac{z}{3}
2
x
+
2
=
−
1
y
+
1
=
3
z
to the plane
x
+
y
+
z
=
3
x+y+z=3
x
+
y
+
z
=
3
. The feet of perpendiculars lie on the line
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