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Mathematics
Mathematics
Problem
If
sin
x
=
−
2
6
5
\sin x=\frac{-2 \sqrt{6}}{5}
sin
x
=
5
−
2
6
and
x
x
x
lies in quadrant III, then
cot
x
\cot x
cot
x
is: a)
3
2
6
\frac{3}{2 \sqrt{6}}
2
6
3
b)
1
2
6
\frac{1}{2 \sqrt{6}}
2
6
1
c)
−
1
2
6
\frac{-1}{2 \sqrt{6}}
2
6
−
1
d)
−
3
2
6
\frac{-3}{2 \sqrt{6}}
2
6
−
3
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