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Problems
Let
C
(
x
)
=
∫
x
3
(
t
2
−
4
)
d
t
+
∫
1
x
2
(
t
2
−
4
)
d
t
,
x
>
0.
C(x)=\int_{x}^{3} \bigl(t^{2}-4\bigr)\,dt+\int_{1}^{x^{2}} \bigl(t^{2}-4\bigr)\,dt, \qquad x>0.
C
(
x
)
=
∫
x
3
(
t
2
−
4
)
d
t
+
∫
1
x
2
(
t
2
−
4
)
d
t
,
x
>
0.
…
Mathematics
Problem
Let
C
(
x
)
=
∫
x
3
(
t
2
−
4
)
d
t
+
∫
1
x
2
(
t
2
−
4
)
d
t
,
x
>
0.
C(x)=\int_{x}^{3} \bigl(t^{2}-4\bigr)\,dt+\int_{1}^{x^{2}} \bigl(t^{2}-4\bigr)\,dt, \qquad x>0.
C
(
x
)
=
∫
x
3
(
t
2
−
4
)
d
t
+
∫
1
x
2
(
t
2
−
4
)
d
t
,
x
>
0.
Which of the following is equal to
C
′
(
x
)
C'(x)
C
′
(
x
)
? a)
2
x
5
+
x
2
−
8
x
−
4
2x^{5}+x^{2}-8x-4
2
x
5
+
x
2
−
8
x
−
4
b)
−
2
x
5
+
x
2
+
8
x
−
4
-2x^{5}+x^{2}+8x-4
−
2
x
5
+
x
2
+
8
x
−
4
c)
2
x
5
−
x
2
−
8
x
+
4
2x^{5}-x^{2}-8x+4
2
x
5
−
x
2
−
8
x
+
4
d)
2
x
5
−
x
2
+
8
x
−
4
2x^{5}-x^{2}+8x-4
2
x
5
−
x
2
+
8
x
−
4
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