Mathematics

Mathematics

Problem

Let f(x)={x2−4x+3,0≤x≤2,5−2x,2<x≤4.f(x)=\begin{cases}x^{2}-4x+3,&0\le x\le 2,\\5-2x,&2<x\le 4.\end{cases} Determine the absolute minimum value of ff on the closed interval [0,4][0,4].

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