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Problem
Problem
- Find: a.
∑
k
=
1
∞
3
4
k
\sum_{k=1}^{\infty} \frac{3}{4^k}
∑
k
=
1
∞
4
k
3
b.
∑
k
=
0
∞
6
(
−
2
5
)
k
\sum_{k=0}^{\infty} 6\left(-\frac{2}{5}\right)^k
∑
k
=
0
∞
6
(
−
5
2
)
k
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