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Mathematics
Mathematics
Problem
If
arctan
x
+
arctan
2
x
=
π
4
\arctan x+\arctan 2x=\dfrac{\pi}{4}
arctan
x
+
arctan
2
x
=
4
π
, then
x
x
x
equals a)
−
17
+
3
4
-\dfrac{\sqrt{17}+3}{4}
−
4
17
+
3
b)
1
2
\dfrac{1}{2}
2
1
c)
17
−
3
4
\dfrac{\sqrt{17}-3}{4}
4
17
−
3
d)
17
−
3
2
\dfrac{\sqrt{17}-3}{2}
2
17
−
3
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