Physics

Problem

The work function of cesium is

2.0\,\text{eV}

. Calculate the minimum frequency of light that can just cause photoelectric emission from cesium. (Given:

h = 6.63\times10^{-34}\,\text{J\,s}

1\,\text{eV}=1.6\times10^{-19}\,\text{J}

) a)

6.4\times10^{14}\,\text{Hz}

4.8\times10^{14}\,\text{Hz}

1.25\times10^{15}\,\text{Hz}

3.2\times10^{14}\,\text{Hz}