Physics

Physics

Problem

Which one of the following expressions correctly gives the de Broglie wavelength λ\lambda of a particle of mass mm and charge qq that is accelerated from rest through a potential difference VV? a) λ=hmqV\displaystyle \lambda = \dfrac{h}{\sqrt{m q V}} b) λ=h2mqV\displaystyle \lambda = \dfrac{h}{2\sqrt{m q V}} c) λ=h2π2mqV\displaystyle \lambda = \dfrac{h}{2\pi\sqrt{2 m q V}} d) λ=h2mqV\displaystyle \lambda = \dfrac{h}{\sqrt{2 m q V}}

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