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Physics
Physics
Problem
Which one of the following expressions correctly gives the de Broglie wavelength
λ
\lambda
λ
of a particle of mass
m
m
m
and charge
q
q
q
that is accelerated from rest through a potential difference
V
V
V
? a)
λ
=
h
m
q
V
\displaystyle \lambda = \dfrac{h}{\sqrt{m q V}}
λ
=
m
q
V
h
b)
λ
=
h
2
m
q
V
\displaystyle \lambda = \dfrac{h}{2\sqrt{m q V}}
λ
=
2
m
q
V
h
c)
λ
=
h
2
π
2
m
q
V
\displaystyle \lambda = \dfrac{h}{2\pi\sqrt{2 m q V}}
λ
=
2
π
2
m
q
V
h
d)
λ
=
h
2
m
q
V
\displaystyle \lambda = \dfrac{h}{\sqrt{2 m q V}}
λ
=
2
m
q
V
h
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