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Lebl-Basic-Analysis-I
· Problem 2.4.2
Sequences and Series
Mathematics · cauchy-sequences
Problem
Let
{
x
n
}
n
=
1
∞
\{x_n\}_{n=1}^\infty
{
x
n
}
n
=
1
∞
be a sequence such that there exists a positive
C
<
1
C < 1
C
<
1
and for all
n
n
n
,
∣
x
n
+
1
−
x
n
∣
≤
C
∣
x
n
−
x
n
−
1
∣
.
|x_{n+1} - x_n| \leq C|x_n - x_{n-1}|.
∣
x
n
+
1
−
x
n
∣
≤
C
∣
x
n
−
x
n
−
1
∣.
Prove that
{
x
n
}
n
=
1
∞
\{x_n\}_{n=1}^\infty
{
x
n
}
n
=
1
∞
is Cauchy. Hint: You can freely use the formula (for
C
≠
1
C \neq 1
C
=
1
)
1
+
C
+
C
2
+
⋯
+
C
n
=
1
−
C
n
+
1
1
−
C
.
1 + C + C^2 + \cdots + C^n = \frac{1 - C^{n+1}}{1 - C}.
1
+
C
+
C
2
+
⋯
+
C
n
=
1
−
C
1
−
C
n
+
1
.
Related theory
Sequences Convergence Cauchy Sequences Subsequences
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