Physics

Physics

Problem

Light of frequency

6.0\times10^{14}\,\text{Hz}

produces a stopping potential of

0.7\,\text{V}

for a metal. When the frequency is increased to

9.0\times10^{14}\,\text{Hz}

, the stopping potential becomes

2.2\,\text{V}

. Calculate Planck’s constant

h

. (Take

e = 1.6\times10^{-19}\,\text{C}

.) a)

1.2\times10^{-33}\,\text{J\,s}

b)

6.6\times10^{-34}\,\text{J\,s}

c)

8.0\times10^{-34}\,\text{J\,s}

d)

3.7\times10^{-34}\,\text{J\,s}

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