Physics

Physics

Problem

Two different wires having lengths L1L_1 and L2L_2 , and respective temperature coefficient of linear expansion eta1 eta_1 and eta2 eta_2 , are joined end-to-end. Then the effective temperature coefficient of linear expansion is : [Main Sep. 05, 2020 (II)] a. β1L1+β2L2L1+L2\frac{\beta_1 L_1 + \beta_2 L_2}{L_1 + L_2} b. 2β1β22\sqrt{\beta_1 \beta_2} c. β1+β22\frac{\beta_1 + \beta_2}{2} d. 4β1β2β1+β2L2L1(L2+L1)24 \frac{\beta_1 \beta_2}{\beta_1 + \beta_2} \frac{L_2 L_1}{(L_2 + L_1)^2}

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