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Mathematics
Mathematics
Problem
Prove that
tan
θ
sec
θ
1
+
tan
2
θ
=
sin
θ
\displaystyle \frac{\tan \theta \,\sec \theta}{1+\tan^{2}\theta}=\sin \theta
1
+
tan
2
θ
tan
θ
sec
θ
=
sin
θ
.
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