Show that a commutative diagram
⋯⋯→→Cn+1En+1↘AnBn↙Dn→→CnEn↘
with the two sequences across the top and bottom exact, gives rise to an exact sequence ⋯→En+1→Bn→Cn⊕Dn→En→Bn−1→⋯ where the maps are obtained from those in the previous diagram in the obvious way, except that Bn→Cn⊕Dn has a minus sign in one coordinate.