If x⋅a=0,x⋅b=1,[xab]=1\mathbf{x} \cdot \mathbf{a} = 0, \mathbf{x} \cdot \mathbf{b} = 1, [\mathbf{x} \mathbf{a} \mathbf{b}] = 1…

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Problem

If x⋅a=0,x⋅b=1,[xab]=1\mathbf{x} \cdot \mathbf{a} = 0, \mathbf{x} \cdot \mathbf{b} = 1, [\mathbf{x} \mathbf{a} \mathbf{b}] = 1 and a⋅b≠0\mathbf{a} \cdot \mathbf{b} \ne 0 , then find x\mathbf{x} in terms of a\mathbf{a} and b\mathbf{b} .

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